Transformador de potencia
Author
rixo007
Last Updated
6 years ago
License
Creative Commons CC BY 4.0
Abstract
Transformador de potencia
Transformador de potencia
\documentclass{article}
\usepackage{tikz}
\usepackage[active,tightpage]{preview}
\PreviewEnvironment{tikzpicture}
\setlength{\PreviewBorder}{10pt}%
\usepackage[utf8]{inputenc}
\usepackage{amsmath}
\usepackage{amsfonts}
\usepackage{amssymb}
\usepackage{lmodern}
\usepackage[american, cuteinductors, europeanvoltages]{circuitikz}
\ctikzset{bipoles/thickness=1}
\begin{document}
\begin{circuitikz}
\draw (0,0) to (2,0)
to[L, v^=$V_x$] (4.0,0);
\draw (0,-1.5) to (2,-1.5)
to[L, v^=$V_y$] (4.0,-1.5);
\draw (0,-3) to (2,-3)
to[L, v^=$V_z$] (4.0,-3);
\draw (1,0) to (1,-0.5) to (4,-0.5) to (4,-1.5);
\draw (1,-1.5) to (1,-2) to (4,-2) to (4,-3);
\draw (1,-3) to (1,-3.5) to (4.5,-3.5) to (4.5,0) to (4,0);
\draw (0.25,0) to[open,i^=$I_x$] (0.3,0);
\draw (1,0) to[open,i^=$I_x'$] (1.25,0);
\draw (0.25,-1.5) to[open,i^=$I_y$] (0.3,-1.5);
\draw (1,-1.5) to[open,i^=$I_y'$] (1.25,-1.5);
\draw (0.25,-3) to[open,i^=$I_z$] (0.3,-3);
\draw (1,-3) to[open,i^=$I_z'$] (1.25,-3);
\draw (5,0) to[L, v^>=$V_1$] (7,0)
to[D*, v^<=$V_{D1}$, bipoles/length=0.8cm] (9,0);
\draw (5,-1.5) to[L, v^>=$V_2$] (7,-1.5)
to[D*, v^<=$V_{D2}$, bipoles/length=0.8cm] (9,-1.5);
\draw (5,-3) to[L, v^>=$V_3$] (7,-3)
to[D*, v^<=$V_{D3}$, bipoles/length=0.8cm] (9,-3);
\draw (9,-4.5) to[I, v^<=$V_{L}$, l_=$I_0$] (5,-4.5);
\draw (5,0) to (5,-4.5);
\draw (9,0) to (9,-4.5);
\end{circuitikz}
\end{document}